Given a binary tree, find its maximum depth.
The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node.
Note: A leaf is a node with no children.
Given binary tree [3,9,20,null,null,15,7], 3 / \ 9 20 / \ 15 7 return its depth = 3.
# Definition for a binary tree node.# class TreeNode:# def __init__(self, x):# self.val = x# self.left = None# self.right = NoneclassSolution: defmaxDepth(self, root: TreeNode) ->int: ifnotroot: return0lmax=self.maxDepth(root.left) rmax=self.maxDepth(root.right) returnmax(lmax, rmax) +1
# Definition for a binary tree node.# class TreeNode:# def __init__(self, x):# self.val = x# self.left = None# self.right = NoneclassSolution: defmaxDepth(self, root: TreeNode) ->int: ifnotroot: return0depth=0nodes= [root] whilenodes: depth+=1nodes= [node.leftfornodeinnodesifnode.left] \ + [node.rightfornodeinnodesifnode.right] returndepth